Pattern with nested loop under construction

 Pattern - 1

{
Enter number of rows: 5

* * 
* * * 
* * * * 
* * * * * 
}



#include <stdio.h> int main() { int n; printf("Enter number of rows: "); scanf("%d", &n); for (int i = 1; i <= n; i++) { for (int j = 1; j <= i; j++) { printf("* "); } printf("\n"); } }

 Pattern - 2

{

Enter number of rows: 5

1 2 
1 2 3
1 2 3 4
1 2 3 4 5
}

#include <stdio.h> int main() { int n; printf("Enter number of rows: "); scanf("%d", &n); for (int i = 1; i <= n; i++) { for (int j = 1; j <= i; j++) { printf("%d ",j); } printf("\n"); } }

 Pattern - 3

{

Enter number of rows: 5

2 3 
4 5 6
7 8 9 10
11 12 13 14 15
}

#include <stdio.h> int main() { int n; printf("Enter number of rows: "); scanf("%d", &n); int a = 1; for (int i = 1; i <= n; i++) { for (int j = 1; j <= i; j++) { printf("%d ",a); a++; } printf("\n"); } }

 Pattern - 4

{

Enter number of rows: 5

3 4 
4 5 6
6 7 8 9 
10 11 12 13 14 
}

#include <stdio.h> int main() { int n; printf("Enter number of rows: "); scanf("%d", &n); for (int i = 1; i <= n; i++) { for (int j = 1; j <= i; j++) { printf("%d ",i+j); } printf("\n"); } }

 Pattern - 5

{
Enter number of rows: 5
1
0 1
1 0 1
0 1 0 1
1 0 1 0 1
}

#include <stdio.h> int main() { int n; printf("Enter number of rows: "); scanf("%d", &n); for (int i = 1; i <= n; i++) { for (int j = 1; j <= i; j++) { printf("%d ", (i + j) % 2); } printf("\n"); } }


 Pattern - 6

{
Enter number of rows: 5
1
0 1
1 0 1
0 1 0 1
1 0 1 0 1
}

#include <stdio.h> int main() { int n; printf("Enter number of rows: "); scanf("%d", &n); int a = 1; for (int i = 1; i <= n; i++) { for (int j = 1; j <= i; j++) { printf("%d ",a); a++; } printf("\n"); } }


 Pattern - 7

{
Enter number of rows: 5
5
5 4 
5 4 3
5 4 3 2 
5 4 3 2 1
}


#include <stdio.h> int main() { int n; printf("Enter number of rows: "); scanf("%d", &n); int a = 1; for (int i = 1; i <= n; i++) { int a = 5; for (int j = 1; j <= i; j++) { printf("%d ",5); a--; } printf("\n"); } }

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